Let R be the set of all real numbers and a function ƒ : R → R be defined by ƒ(x) = ax + b, where a, b are constants and a ≠ 0. is ƒ invertible? If it is so, find the inverse of ƒ.

1
Inverse of f exists and ƒ-1 (x) = \(\frac{x-b}{a}\)
2
ƒ is one-to-one but not onto
3
The inverse of ƒ does not exist
4
ƒ is onto but one-to-one
5
Not Attempted

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