A stone falls freely under gravity. It covers distances h1, h2 and h3 in the first 5 seconds, the next 5 seconds and the next 5 seconds respectively. The relation between h1, h2 and h3 is:
1
h1 = 2h2 = 3h3
2
\({h_1} = \frac{{{h_2}}}{3} = \frac{{{h_3}}}{5}\)
3
h2 = 3h1 and h3 = 3h2
4
h1 = h2 = h3