If \(\frac{dx}{dy}=u,\frac{d^2x}{dy^2}=v\), then \(\frac{d^2y}{dx^2}\) is

1
\(-\frac{v}{u^4}\)
2
\(-\frac{v}{u^3}\)
3
\(-\frac{v^2}{u^3}\)
4
\(-\frac{v^2}{u}\)

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