A block of mass m slides along a floor while a force of magnitude F is applied to it at an angle θ as shown in figure. The coefficient of kinetic friction is μk. Then, the block's acceleration 'a' is given by:
(g is acceleration due to gravity)
1
\(\rm - \frac{F}{m}\cos \theta - {\mu _K}\left( {g - \frac{F}{m}\sin \theta } \right)\)
2
\(\rm \frac{F}{m}\cos \theta + {\mu _K}\left( {g - \frac{F}{m}\sin \theta } \right)\)
3
\(\rm \frac{F}{m}\cos \theta - {\mu _K}\left( {g + \frac{F}{m}\sin \theta } \right)\)
4
\(\rm \frac{F}{m}\cos \theta - {\mu _K}\left( {g - \frac{F}{m}\sin \theta } \right)\)