The value of \(\int {\frac{{\log x}}{{{{(x + 1)}^2}}}dx\,\,\,\,\,} \)is
1
\(\frac{{ - \log x}}{{x + 1}}\) + log x - log (x + 1)
2
\({\frac{{\log x}}{{(x + 1)}}}\) + log x - log (x + 1)
3
\({\frac{{\log x}}{{x + 1}}}\) log x - log (x + 1)
4
\({\frac{{-\log x}}{{x + 1}}}\) - log x - log (x +1)