Let z ∈ C with Im(z) = 10 and it satisfies \(\frac{{2z - n}}{{2z + n}} = 2i - 1\) for some natural number n. Then:

1
n = 20 and Re(z) = -10
2
n = 40 and Re(z) = 10
3
n = 40 and Re(z) = -10
4
n = 20 and Re(z) = 10

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