If α and β are the root of the equation 3x2 - 6x + 4 = 0 the value of : \(\left(\frac{\alpha}{\beta}+ \frac{\beta}{\alpha}\right) + 2 \left(\frac{1}{\alpha} + \frac{1}{\beta}\right) + 3\alpha \beta\) will be

1
12
2
8
3
\(\frac{3}{2}\)
4
16

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