If \(x=\frac{2 \sin \theta}{(1+\cos \theta+\sin \theta)}\), then the value of \(\frac{1-\cos \theta+\sin \theta}{(1+\sin \theta)}\) is:

1
\(\frac{x}{(1+x)}\)
2
X
3
\(\frac{1}{\mathrm{x}}\)
4
\(\frac{(1+x)}{x}\)

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