If y = tan−1\( \left(\frac{x}{\sqrt{1−x^{2}}}\right)\) + sec−1\( \left(\frac{1}{\sqrt{1−x^{2}}}\right)\), |x| < 1, then \(\frac{dy}{dx}\) equals :

1
\(\frac{2}{\sqrt{1−x^{2}}}\)
2
\(\frac{1}{\sqrt{1−x^{2}}}\)
3
\(2\sqrt{1−x^{2}}\)
4
\(\sqrt{1−x^{2}}\)

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