Find the electric field at point P (as shown in figure) on the perpendicular bisector of a uniformly charged thin wire of length L carrying a charge Q. The distance of the point P from the centre of the rod is \({\rm{a = }}\frac{{\sqrt 3 }}{2}{\rm{L}}{\rm{.}}\)
1
\(\frac{{\rm{Q}}}{{3\pi { \varepsilon _0}{{\rm{L}}^{\rm{2}}}}}\)
2
\(\frac{{\rm{Q}}}{{4\pi { \varepsilon _0}{{\rm{L}}^{\rm{2}}}}}\)
3
\(\frac{{\sqrt 3 {\rm{Q}}}}{{4\pi { \varepsilon _0}{{\rm{L}}^{\rm{2}}}}}\)
4
\(\frac{{\rm{Q}}}{{2\sqrt 3 \pi { \varepsilon _0}{{\rm{L}}^{\rm{2}}}}}\)