A conducting wire of length 'l', area of cross-section A and electric resistivity ρ is connected between the terminals of a battery. A potential difference V is developed between its ends, causing an electric current.

If the length of the wire of the same material is doubled and the area of cross-section is halved, the resultant current would be:

1
\(\rm4\frac{{VA}}{{\rho l}}\)
2
\(\rm\frac14\frac{{\rho l}}{{VA}}\)
3
\(\rm\frac14\frac{{VA}}{{\rho l}}\)
4
\(\rm\frac34\frac{{VA}}{{\rho l}}\)

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation