A parallel plate capacitor with plate area A and plate separation d, with a vacuum between the plates, has a capacitance C0.
The space between the plates is filled with two slabs of the same area but thicknesses (d/4) and (3d/4) made of material of dielectric constant 2 and 4, respectively. The capacitance of the capacitor is now:
1
\((\frac{12}{5})\) C0
2
\((\frac{6}{5})\) C0
3
\((\frac{8}{5})\) C0
4
\((\frac{16}{5})\) C0