A sinusoidal wave f1(t) = 3 sin ω t is superposed on another periodic wave f2(t) which is also oscillating with the same frequency. If the resultant wave is a sinusoidal wave, which is out of phase with f1(t) by 53.1° ; then the wave f2(t) would be-

[Given tan 53.1° = 1.33]

1
f2(t) = 3 sin (ωt)
2
f2(t) = 4 sin (ωt + 53.1°)
3
f2(t) = 3 cos (ωt - 53.1°)
4
f2(t) = 4 cos (ωt)

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