If y = \(\frac{x \sqrt{x^2−16}}{2} − 8 \ln\left|x + \sqrt{x^2−16}\right|\), then what is \(\frac{\text{dy}}{\text{dx}}\) equal to ?
1
\(\text{x}\sqrt{\text{x}^2−16}\)
2
\(\text{x}−\sqrt{\text{x}^2−16}\)
3
\(\sqrt{\text{x}^2−16}\)
4
\(4\sqrt{\text{x}^2−16}\)