A thin uniform rod of mass 1 kg and length 1 m is hanged at one end to the ground floor. It originally stands vertically and allowed to fall to the ground. If the rod hits the ground with angular speed ω then the correct statement is
(Assume g = 10 m/s2)
1
ω = \(\sqrt {30} \) rad/s
2
ω = \(\sqrt {20} \) rad/s
3
ω = 5 rad/s
4
ω = 6 rad/s