In the equation
\({\cos ^{ - 1}}\left( {\frac{{1 - {a^2}}}{{1 + {a^2}}}} \right) - {\cos ^{ - 1}}\left( {\frac{{1 - {b^2}}}{{1 + {b^2}}}} \right) = 2{\tan ^{ - 1}}x\)
value of x is
1
\(\frac{{a + b}}{{1 + ab}}\)
2
\(\frac{{a - b}}{{1 + ab}}\)
3
\(\frac{{a - b}}{{1 - ab}}\)
4
None of the above