All the four quantum numbers of last electron of sodium atom are

1
n = 3, l = 0, m = 0, S = \(+\frac{1}{2}\) 
2
n = 3, l = 1, m = +1, s = \(+\frac{1}{2}\)
3
n = 3, l = 2, m = +1, s = \(+\frac{1}{2}\)
4
n = 2, l = 0, m = 0, s = \(+\frac{1}{2}\)

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