The equation of the normal at the point (2, √7) to the hyperbola 16x2 - 9y2 = 1 is:

1
\(32y + 9\sqrt 7 x = \sqrt 7 \)
2
\(32y + 9\sqrt 7 x = 50\sqrt 7 \)
3
\(32y + 9\sqrt 7 x = 1\)
4
\(32y + 9\sqrt 7 x = 2\sqrt 7\)

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