If S1 = {x ϵ R ∶ x2 + | x | - 2 = 0} and S2 = {x ϵ R ∶ x2 + x - 2 = 0}, then

1
S1 ∪ S2 has 4 elements.
2
S1 ∪ S2 has 2 elements.
3
S1 ∩ S2 has 2 elements.
4
S1 ∩ S2 has 1 elements.

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