∆ABC is similar to ∆DEF and the ratio of the area of triangle ABC to triangle DEF is 25 ∶ 144. If AB = p cm, AC = q cm and BC = r cm, then DE = ?
1
\( \frac{5}{12} \mathrm{p}\)
2
\(\frac{12}{5} \mathrm{q} \)
3
\( \frac{12}{5} \mathrm{p}\)
4
\( \frac{5}{12} \mathrm{q}\)