Mathematics Combinatorics Recurrence Relations

The solution to the recurrence equation \(T(2^k)=3T(2^{k-1})+1\), T(1) = 1 is:

1
\(2^{\log_3k}\)
2
2k
3
\(\frac{3^{k+1}-1}{2}\)
4
\(3^{\log_2k}\)

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