Mathematics Combinatorics Recurrence Relations

The solution of the recurrence relation \(a_n=6a_{n-1}-9a_{n-2}\), a0 = 1, a1 = 6 is:

1
an = (1 + n)3n
2
an = (n - 1)3n
3
an = (1 + n)6n
4
an = (1 - n)3n

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