For the following probability distribution
| X | 1 | 2 | 3 | 4 |
| P(X) | \(\frac{1}{10}\) | \(\frac{1}{5}\) | \(\frac{3}{10}\) | \(\frac{2}{5}\) |
E(X2) is equal to
1
3
2
5
3
7
4
10
For the following probability distribution
| X | 1 | 2 | 3 | 4 |
| P(X) | \(\frac{1}{10}\) | \(\frac{1}{5}\) | \(\frac{3}{10}\) | \(\frac{2}{5}\) |
E(X2) is equal to