If x = \(\rm {{1\ -\ t}\over {1\ +\ t}}\) and y = \(\rm {2t\over {1\ +\ t}}\), then find the value of \(\rm {d^2y\over dx^2}\).

1
\(\rm\frac{1}{y}\)
2
\(\rm\frac{-1}{y}\)
3
\(\rm {{-1}\over {y^3}}\)
4
0

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