The minimum value of \(\frac{{9 \cdot {3^{2x}} + 6 \cdot {3^x} + 4}}{{9 \cdot {3^{2x}} - 6 \cdot {3^x} + 4}}\) is

1
-1
2
\(\frac{1}{2}\)
3
\(\frac{1}{4}\)
4
\(\frac{1}{3}\)

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