A box contains 3 orange balls, 3 green balls and 2 blue balls. Three balls are drawn at random from the box without replacement. The probability of drawing 2 green balls and one blue ball is
1
\(\frac{3}{28}\)
2
\(\frac{2}{21}\)
3
\(\frac{1}{28}\)
4
\(\frac{167}{168}\)