Sum to 'n' terms of the series \(\dfrac{1}{1.2.3}+\dfrac{3}{2.3.4}+\dfrac{5}{3.4.5}+\dfrac{7}{4.5.6}+...\) is:

1
\(\dfrac{n(3n+1)}{4(n+1)(n+2)}\)
2
\(\dfrac{n(n+2)}{(n+3)(n+4)}\)
3
\(\dfrac{n(n+2)}{(n+1)(n+4)}\)
4
\(\dfrac{n(n+1)}{2(n+1)(n+4)}\)

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