If three concurrent straight lines AD, BE, and CF are drawn from the angular points of a triangle ΔABC to meet the opposite sides such that \(\dfrac{AF}{FB}\times\dfrac{BD}{DC} = \dfrac{1}{3}\), then by applying Ceva's theorem, \(\dfrac{EA}{EC}\) is equal to:
1
1/3
2
3/2
3
2/3
4
1