Apply Chinese Remainder Theorem to solve
X = 3 (mod 5), X = 5 (mod 7). The common solution is:
1
X = 33 (mod 35)
2
X = 31 (mod 5)
3
X = 27 (mod 35)
4
X = 28 (mod 35)
Apply Chinese Remainder Theorem to solve
X = 3 (mod 5), X = 5 (mod 7). The common solution is: