The solution set of x for the following inequality is:

\(\frac{1}{4}\left( {\frac{{6x}}{{10}} + 8} \right) \ge \frac{1}{6}\left( {x - 12} \right)\)

1
x ≥ 240
2
x ≥ -240
3
x ≤ -240
4
x ≤ 240

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