The point at which the normal to the curve y = x + \(\frac{1}{x}\), x > 0 is perpendicular to the line 3x - 4y - 7 = 0 is :

1
(2, 5/2)
2
(±2, 5/2)
3
(-1/2, 5/2)
4
(1/2, 5/2)

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