If ƒ(x) = \( \frac{1-x}{2+x}\), then find ƒ' (x).

1
\( \frac{2}{({3+x})^2}\)
2
\( \frac{-3}{({2+x})^2}\)
3
\( \frac{1}{({x-2})^2}\)
4
\( \frac{1}{({2+x})^2}\)

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