If \(\frac{4}{3}\) of the difference of \(2\frac{1}{4}\) and \(1\frac{2}{3}\) is added to \(\frac{1}{2}\) of the difference of \(2\frac{1}{3}\) and \(1\frac{2}{7}\), then result is :
1
\(\frac{63}{82}\)
2
\(\frac{82}{63}\)
3
\(-\frac{63}{82}\)
4
\(-\frac{82}{63}\)