Teaching DSSSB PGT Mock Test 2025 Mathematics Differential Equations

Solution of the differential equation \(\frac{d^2y}{dx^2}-2y^3-2y=0; y(0)=0,y'(0)=1\) is

1
y = cot x + 1
2
y = tan x + 1
3
y = tan x
4
y = cot x
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