Teaching DSSSB PGT Mock Test 2025 Mathematics Differential Equations Solution of Differential Equations
The equation of the curve satisfying the differential equation y2(x2 + 1) = 2xy1 passing through the point (0,1) and having slope of tangent at x = 0 as 3 is
1
y = x3 + 3x + 1
2
y = x3 - 3x + 1
3
y = x2 + 3x + 1
4
y = x2 - 3x + 1