The given expression is equal to:
\(\frac{\left(1+\tan ^2 A\right)}{\operatorname{cosec}^2 A \cdot \tan A}\)
1
sec2 A
2
sec A
3
Tan A
4
Tan2 A
The given expression is equal to:
\(\frac{\left(1+\tan ^2 A\right)}{\operatorname{cosec}^2 A \cdot \tan A}\)