The matrix form of the linear system \(\frac{{dx}}{{dt}} = 3x - 5y\) and \(\frac{{dy}}{{dt}} = 4x + 8y\) is
1
\(\frac{d}{{dt}}\left\{ {\begin{array}{*{20}{c}} x\\ y \end{array}} \right\} = \left[ {\begin{array}{*{20}{c}} 3&{ - 5}\\ 4&8 \end{array}} \right]\left\{ {\begin{array}{*{20}{c}} x\\ y \end{array}} \right\}\)
2
\(\frac{d}{{dt}}\left\{ {\begin{array}{*{20}{c}} x\\ y \end{array}} \right\} = \left[ {\begin{array}{*{20}{c}} 3&8\\ 4&{ - 5} \end{array}} \right]\left\{ {\begin{array}{*{20}{c}} x\\ y \end{array}} \right\}\)
3
\(\frac{d}{{dt}}\left\{ {\begin{array}{*{20}{c}} x\\ y \end{array}} \right\} = \left[ {\begin{array}{*{20}{c}} 4&{ - 5}\\ 3&8 \end{array}} \right]\left\{ {\begin{array}{*{20}{c}} x\\ y \end{array}} \right\}\)
4
\(\frac{d}{{dt}}\left\{ {\begin{array}{*{20}{c}} x\\ y \end{array}} \right\} = \left[ {\begin{array}{*{20}{c}} 4&8\\ 3&{ - 5} \end{array}} \right]\left\{ {\begin{array}{*{20}{c}} x\\ y \end{array}} \right\}\)