Let X1, X2, X3, X4, X5 be i.i. d. random variables having a continuous distribution function. Then

P(X1 > X2 > X3 > X4 > X5 ∣ X1 = max(X1, X2, X3, X4, X5)) equals

1
\(\frac{1}{4}\)
2
\(\frac{1}{5}\)
3
\(\frac{1}{4!}\)
4
\(\frac{1}{5!}\)
5
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