The differential equation
\(\left\{\begin{aligned} \frac{d y}{d t} &=y^{\frac{2k}{k+2}} \text { for } t>0, \\ y(0) &=0 \end{aligned}\right.\)
has infinitely many solution if
1
0 < k < 3/2
2
1 < k < 3
3
0 < k < 1
4
0 < k < 2
5
Question Not Attempted
The differential equation
\(\left\{\begin{aligned} \frac{d y}{d t} &=y^{\frac{2k}{k+2}} \text { for } t>0, \\ y(0) &=0 \end{aligned}\right.\)
has infinitely many solution if