If the system of equations

x + (√2 sin α)y + (√2 cos α)z = 0

x + (cos α)y + (sin α)z = 0

x + (sin α)y - (cos α)z = 0

has a non-trivial solution, then \(\alpha \in \left(0, \frac{\pi}{2}\right)\) is equal to:

1
\(\frac{3\pi}{4}\)
2
\(\frac{7\pi}{24}\)
3
\(\frac{5\pi}{24}\)
4
\(\frac{11\pi}{24}\)
5
Question Not Attempted

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