Teaching Haryana (HPSC) Assistant Professor Mock Test 2025 Chemical Sciences Chemical Kinetics Enzyme Kinetics
In an enzyme-catalysed reaction
\( \mathrm{E}+\mathrm{S} \underset{k_{-1}}{\stackrel{k_1}{\rightleftharpoons}} \mathrm{ES} \stackrel{k_2}{\longrightarrow} \mathrm{E}+\mathrm{P} \)
\(k_2=3.42 \times 10^4 \mathrm{~s}^{-1} . \text { If }[E]_0\) = \(1 \times 10^{-2} \mathrm{~mol} \mathrm{dm}^{-3} \), the magnitude of maximum velocity and turnover number using Michaelis-Menten kinetics are
1
\(3.42 \times 10^2 \mathrm{~mol}\ \mathrm{dm}^{-3} \mathrm{~s}^{-1} ; \) \(3.42 \times 10^4 \mathrm{~s}^{-1}\)
2
\(3.42 \times 10^6 \mathrm{~mol}\ \mathrm{dm}^{-3} \mathrm{~s}^{-1} ;\) \( 3.42 \times 10^4 \mathrm{~s}^{-1}\)
3
\(3.42 \times 10^4 \mathrm{~mol}\ \mathrm{dm}^{-3} \mathrm{~s}^{-1} ; \) \(3.42 \times 10^6 \mathrm{~s}^{-1}\)
4
\(3.42 \times 10^4 \mathrm{~mol}\ \mathrm{dm}^{-3} \mathrm{~s}^{-1} ;\) \( 3.42 \times 10^2 \mathrm{~s}^{-1}\)
5
Question Not Attempted