Expression ((¬ p ∨ ¬ q) ∧ (p ∧ q)) ∨ r → p ∧ (q ∨ r) is logically equivalent is

1
r → p ∧ (q ∨ r)
2
p → q ∧ (p ∨ r)
3
r → q ∧ (q ∨ r)
4
q → p ∧ (q ∨ r)
5
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