Considering equal processing time for each segment, speed-up S achieved by a K-segment instruction pipeline operating on straight sequence of N instructions is given by:
1
\(S=\frac{K(N-K)}{K+N-1}\)
2
\(S=\frac{K+N}{KN}\)
3
\(S=\frac{K(K+1)}{(K+1)N}\)
4
\(S=\frac{KN}{K+N-1}\)
5
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