Teaching Haryana (HPSC) Assistant Professor Mock Test 2025 Physics Capacitance The Parallel Plate Capacitor
Consider a parallel plate capacitor of plate area A and plate separation d. A potential difference V0 is applied between the plates. The battery is then disconnected and a dielectric slab of thickness d/2 and dielectric constant K is placed between the plates, as shown in figure.
The potential difference between the plates after the insertion of slab is V. The ratio V/V0 is
1
\(\rm\frac{1+K}{2 K}\)
2
\(\rm\frac{1+ K}{K}\)
3
\(\rm\frac{2 K}{1+ K}\)
4
\(\rm\frac{K}{1+K}\)
5
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