A particle of mass m slides under the gravity without friction along the parabolic path y = ax2, as shown in the figure. Here a is a constant.
The Lagrange’s equation of motion of the particle for above question is given by
1
ẍ = 2gax
2
m(1 + 4a2x2)ẍ = −2mgax − 4ma2xẋ2
3
m(1 + 4a2x2)ẍ = 2mgax + 4ma2xẋ2
4
ẍ = −2gax
5
Question Not Attempted