The standard Gibbs free energy change of the reaction shown below is –2.7 kJ mol–1 .
Sn(s) + Pb2+ = Sn2+ + Pb(s)
Given that E0 (Pb2+/Pb) is –0.126 V, the value of E0 (Sn2+/Sn) in V is _____ (up to two decimal places)
1
-0.14
2
20.0
3
0.20
4
-0.32
5
Question Not Attempted