The ground state wavefunction of a particle in a three-dimensional potential is given by \(\psi(r)=A e^{-a r^2}\), where A is the normalisation constant r, is the radial coordinate and a is a constant. The value of A is given by

1
\(\left(\frac{a}{2 \pi}\right)^{1 / 4}\)
2
\(\left(\frac{2 a}{\pi}\right)^{1 / 2}\)
3
\(\left(\frac{2 a}{\pi}\right)^{3 / 4} \)
4
\(\left(\frac{a}{2 \pi}\right)^{3 / 2} \)
5
Question Not Attempted

Sponsored

hivanix.in

Visit

This quiz is brought to you by hivanix.in

🌐 Web App Development

Quick Navigation