Consider the linear ordinary differential equation of the form \(y''(x) + 4y'(x) + 4y(x) = 0 \)  with initial conditions y (0) = 1 and y'(0) = 0. Then, which of the following is the solution of the differential equation?

1
y(x) = e(-2x) + x e(-2x)
2
y(x) = e^(-2x) + 2x e^(-2x)
3
y(x) = e^(-2x) - x e^(-2x)
4
y(x) = e^(-2x) - 2x e^(-2x)
5
Question Not Attempted

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