A bag contains 6 white balls and 4 red balls. Three balls are drawn from the bag one by one without replacement. What is the probability that the first ball drawn is white, the second ball drawn is red, and the third ball drawn is white?

1
\(\frac{1}{6}\)
2
\(\frac{3}{50}\)
3
\(\frac{3}{20}\)
4
\(\frac{1}{5}\)
5
Question Not Attempted

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