In the circuit below, D is an ideal diode, the source voltage Vs = V0 sin ωt is a unit amplitude sine wave and Rs = RL.
The average output voltage, VL, across the load resistor RL is
1
\(\frac{{\rm{1}}}{{{\rm{2\pi }}}}{{\rm{V}}_{\rm{0}}}\)
2
\(\frac{3}{{{\rm{2\pi }}}}{{\rm{V}}_{\rm{0}}}\)
3
3V0
4
V0